Question

2x (3x^2 + 5) -10.

Answer 1

$\huge\mathfrak\color {teal}☆AnSwEr☆$

$\sf\orange {\underline {\sf ☆Given☆}}$

$2x( {3x}^{2} + 5) - 10 = 0$

$\sf\blue {\underline {\sf ☆To\:Find\:x☆}}$

$4 {x}^{3} + 5 = 10$

$4 {x}^{3} = 10 - 5$

$4 {x}^{3} = 5$

${x}^{3} = \frac{5}{4}$

$\huge{or}$

${x}^{3} = 1 \times \frac{1}{4}$

$\huge\mathcal\color {grey}Might\:Help\:You$