Question

in figure if ab parallel cd parallel ef , pq parallel rs ,angle rod=25 degree and angle cqp=60 degree then qrs =?

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Answer 1

Answer:

145°

Step-by-step explanation:

AB || CD || EF (Given)

PQ || RS  (Given)

∠ RQD = 25° (Given)

∠ CQP = 60° (Given)

According to the figure -

∠ DQR = ∠ QRA = 25° ( Alternate interior angles)

∠ PQC = ∠ BRS = 60°  ( Alternate exterior angles)

∠ QRA + ∠ ARS = ∠QRS  

= ∠QRA + (180° – ∠BRS) [ Linear pair axioms]

= 25° + 180° - 60°

= 205° - 60°

= 145°

Therefore, the value of ∠QRS is 145°.

Answer 2

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