Question

2x+3y=0
3x+4y=5
solve this by substitution method and elimination method?

Answer 1

See the attach file for ans

Answer 2

Answer:

x=15 and y =-10

Step-by-step explanation:

Given :$2x+3y=0$

          $3x+4y=5$

To find : solve this by substitution method and elimination method

Solution:

Substitution method :

$2x+3y=0$---A

$3x+4y=5$ ----B

Substitute the value of x from A in B

$3(\frac{-3y}{2})+4y=5$

$\frac{-9y}{2}+4y=5$

$-9y+8y=10$

$y=-10$

Substitute the value of y in A

$2x+3(-10)=0$

$2x-30=0$

$2x=30$

$x=15$

So, x=15 and y =-10

Elimination method:

$2x+3y=0$---A

$3x+4y=5$ ----B

Multiply A with 3 and B with 2

$6x+9y=0$---C

$6x+8y=10$ ----D

Subtract C from D

$6x+8y-6x-9y=10$

$-y=10$

$y=-10$

Substitute the value of y in A

$2x+3(-10)=0$

$2x-30=0$

$2x=30$

$x=15$

So, x=15 and y =-10