Question

2x + 3y = 0 and 4x + 6y = 18 by substitution method
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Answer 1

Answer:

$\large\boxed{\textnormal{No solutions}}$

Step-by-step explanation:

To solve this problem, first you have to isolate by the x or y on one side of the equation to find the substitution.

Given:

2x+3y=0 and 4x+6y=18 with using substitution method.

Solutions:

First, isolate by the x from left to right.

$\displaystyle 2x+3y=0$

Subtract 3y from both sides.

$\displaystyle 2x+3y-3y=0-3y$

Solve.

$\displaystyle 2x=-3y$

Divide by 2 from both sides.

$\displaystyle \frac{2x}{2}=\frac{-3y}{2}$

Solve.

$\displaystyle x=-\frac{3y}{2}$

Substitute (solve/simplify.)

x=-3y/2

$\begin{bmatrix}4(-\frac{3y}{2})+6y=18\end{bmatrix}$

Rewrite the problem down. (refine.)

Solve.

$\displaystyle 4(-\frac{3}{2})+6y=18$

$\displaystyle -18=0$

-18=0, is not true, because the system of equations don't have any of these solutions.

The correct answer is no solutions.