2x-3y+1=0,3x+4y-5=0 using elimination method
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Answer:
y=13/17 and x=39/34
Step-by-step explanation:
let the first be equation no 1 and second be equation no 2.
multiply eq 1 X3 and eq 2 X2
we get
6x-9y+3=0 eq 3
6x+8y-10=0. eq 4
change the - to + and + to - of eq 4
so when we eliminate, we will get
- 17y+13=O
-17y=-13
17y=13
then y=13/17. sub this on eq 1
2x-3(13/17)+1=0
2x-39/17=0.
-39/17=-2x
2x=39/17
then x=39/17X2=39/34.
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