Question

calculate the ratio of longest wavelength of Liman series to the shortest wavelength of balma series​

Answer 1

Answer:

For Lyman series, n1=1. For shortest wavelength in Lyman series (i.e., series limit), the energy difference in two states showing transition should be maximum, i.e., n2=∞. For longest wavelength in Lyman series (i.e., first line), the energy difference in two states showing transition should be minimum, i.e., n2=2.

please please mark me as brainliest....

Answer 2

Answer:

For Lyman series, n1=1. For shortest wavelength in Lyman series (i.e., series limit), the energy difference in two states showing transition should be maximum, i.e., n2=∞. For longest wavelength in Lyman series (i.e., first line), the energy difference in two states showing transition should be minimum, i.e., n2=2.: