Math, asked by gurpreet26sardar, 6 months ago

-2x+3y=-1
3y-2x=7.Solve by elimination method​

Answers

Answered by nmchopra
0

Answer:

x = 19/5 and y = 11/5

Step-by-step explanation:

-2x+3y=-1    ..... eqn 1

3y-2x=7 or -2x+3y=7     ..... eqn 2

As the LHS of both the equations are the same but their RHS are different, this question is incorrect.

However, if you meant 3x-2y=7 instead of 3y-2x=7, then it can be solved.

By adding and subtracting them as shown:

Adding them,

-2x+3y=-1    ..... eqn 1

3x-2y=7    ..... eqn 3

========

x+y=6    ..... eqn 4

=======

Subtracting them,

-2x+3y= -1    ..... eqn 1

±3x+2y= ±7    ..... eqn 3

========

-5x+5y=-8

or x-y=8/5     ..... eqn 5

Adding eqn 4 and eqn 5,

x+y=6

x-y=8/5

========

2x=6+8/5 = 38/5

x=38/10 = 19/5

Substituting this value of x in eqn 1, we get

-2x+3y=-1

-2(38/10) + 3y = -1

-76/10 + 3y = -1

3y = -1 + 76/10 = (-10+76)/10

3y= 66/10

y=22/10 = 11/5

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