2x+3y =1 x-4y=5 elimination method
Answers
Step-by-step explanation:
Given:-
2x+3y =1,
x-4y=5
To find:-
Solve the given pair of linear equations by Elimination method?
Solution:-
Given pair of linear equations are
2x+3y =1--------(1)
x-4y=5--------(2)
On multiplying (2) with 2 both sides
2x -8y = 10 -----(3)
On Subtracting (1) from (3) for eliminating the variable x
2x -8y = 10
2x+3y =1
(-)
_________
0 -11y = 9
_________
=> -11y = 9
=> y = -9/11
On Substituting the value of y in (1) then
2x +3(-9/11) = 1
=> 2x -(27/11) = 1
=> 2x = 1+(27/11)
=> 2x = (11+27)/11
=> 2x = 38/11
=> x = 38/(11×2)
=>x = 38/22
=> x = 19/11
Therefore, x = 19/11 and y = -9/11
Answer:-
The solution for the given pair of linear equations in two variables is (19/11 , -9/11)
Check:-
If x = 19/11 and y = -9/11
LHS of (1)
=> 2(19/11)+3(-9/11)
=> (38/11)+(-27/11)
=> (38-27)/11
=> 11/11
=>1
=> RHS
LHS = RHS
LHS of (2)
(19/11)-4(-9/11)
=> (19/11) +(36/11)
=> (19+36)/11
=> 55/11
=>5
=>RHS
LHS = RHS
Verified the given relations
Used Method:-
- Method of Elimination