Question

Solve : √4x+1+√x+3 √4x+1−√x+3 = 4 1 [By using endo properties of proportion]

Answer 1

Given:

√4x+1+√x+3 √4x+1−√x+3 = 4 1

To find:

Solve : √4x+1+√x+3 √4x+1−√x+3 = 4 1 [By using endo properties of proportion]

Solution:

From given, we have,

√4x+1+√x+3 / √4x+1−√x+3 = 4 / 1

using componendo and dividendo,

a/b = c/d

⇒ (a+b)/(a-b) = (c+d)/(c-d)

so, we have,

[(√4x+1+√x+3) + (√4x+1−√x+3)]  / [(√4x+1+√x+3) - (√4x+1−√x+3)] = (4+1) / (4-1)

(2√4x+1) / (2√x+3) = 5/3

(√4x+1) / (√x+3) = 5/3

squaring on both the sides, we get,

(4x+1)/(x+3) = 25/9

9(4x + 1) = 25(x + 3)

36x + 9 = 25x + 75

11x = 66

x = 6

Answer 2

A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg. A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg.