Question

2x - 3y=10 and xy=16
find value of 8x^3 - 27y^3
please fast

Answer 1

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Answer 2

Given Equation is 2x - 3y = 10 and xy = 16.

On cubing both sides, we get

(2x - 3y)^3 = (10)^3

8x^3 - 27y^3 - 3 * 2x * 3y(2x - 3y) = 1000

8x^3 - 27y^3 - 18xy(3x - 2y) = 1000

8x^3 - 27y^3 - 18(16)(10) = 1000

8x^3 - 27y^3 - 2880 = 1000

8x^3 - 27y^3 = 1000 + 2880

8x^3 - 27y^3 = 3880.


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