Question

2x+3y=12,3x-2y=5 than find x and you value

Answer 1

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Answer 2

$2x+3y=12 \\ 3y=12-2x \\ y = \frac{(12 - 2x)}{3 } \\ y = \frac{12}{3} - \frac{2x}{3} \\ y = 4 - \frac{2x}{3}$
$3x - 2y = 5 \\ 3x - 2(4 - \frac{2x}{3} ) = 5 \\ 3x - 8 + \frac{4x}{3 } = 5 \\ \frac{13x}{3} = 13 \\ x = 3$
$y = 4 - \frac{2x}{3} \\ y = 4 - 2 \\ y = 2 \\ x = 3$