2x-3y+13=0,3x-2y+12=0
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Heya,
I am using the elimination method here,
Let 2x -3y= -13 be eqn (1)
and,3x -2y= -12 be eqn (2)
Now, multiply 3 with eqn (1)
and 2 with eqn (2)...
So,
6x -9y= -39
6x -4y= -24
Subtracting eqn (1) and eqn (2)
we get :
-5y = -15
y = 15/5
y = 3
Now put the value of y in eqn (1)
2x -9 = -13
2x = -4
x = -2
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