Question

without solving the following quadratic equation find the value of m for which the given equation has real and equal roots:x^2+2(m-1)X+(m+5)=0​

Answer 1

Step-by-step explanation:

x^2+2(m-1) x+(m+5) =0

m=1

x^2+0+6=0

x^2=-6

x=√6i, -√6i