2x+3y =13 and xy=6 find the value of 8x^3 + 27 y^3
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Answer:
(2x)³+(3y)³
(2x+3y)(4x²-6xy+9x²)
(2x+3y)(4x²+9x²-6xy)
(2x+3y){(2x)²+(3x)²-6xy}
(2x+3y){(2x+3y)²-2xy-6xy}
(2x+3y)(2x+3y)²-8xy
(2x+3y)³-8xy
(13)³-8×6
2197-48
2149
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