Math, asked by shalinianilanchan, 7 months ago

2x-3y=14; 5x+2y-17=0 solve the equation by equating the coefficient of variables.​

Answers

Answered by saeeshinde
0

Answer:

By cross multiplication method

x=

(a

1

b

2

−a

2

b

1

)

(b

1

c

2

−b

2

c

1

)

&

y=

(a

1

b

2

−a

2

b

1

)

(c

1

a

2

−c

2

a

1

)

Where a

1

x+b

1

y+c

1

=0 & a

2

x+b

2

y+c

2

=0

are 2 lines

⇒x=

2(−2)−(3×3)

3(−6)−(−2)(−17)

=

−13

−52

=4

y=

2(−2)−(3×3)

(−17)3−(−6)2

=

−13

−39

=3

x=4&y=3

Step-by-step explanation:

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Answered by LeParfait
0

Solution:

The given equations are

  • 2x - 3y = 14 .....(i)
  • 5x + 2y = 17 .....(ii)

To equate the coefficient of variables, we use elimination method.

Multiply (i) by 5 and (ii) by 2, we get

  • 10x - 15y = 70
  • 10x + 4y = 34

We see that the coefficient of x is 10 in both the equations.

On subtraction, we get

  • 19y = - 36
  • or, y = - 36/19

Putting y = - 36/19 in (i), we get

  • 2x + 108/19 = 14
  • or, 2x = 14 - 108/19
  • or, 2x = 158/19
  • or, x = 79/19

Answer:

Required solution is x = 79/19, y = - 36/19.

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