2x-3y=14; 5x+2y-17=0 solve the equation by equating the coefficient of variables.
Answers
Answered by
0
Answer:
By cross multiplication method
x=
(a
1
b
2
−a
2
b
1
)
(b
1
c
2
−b
2
c
1
)
&
y=
(a
1
b
2
−a
2
b
1
)
(c
1
a
2
−c
2
a
1
)
Where a
1
x+b
1
y+c
1
=0 & a
2
x+b
2
y+c
2
=0
are 2 lines
⇒x=
2(−2)−(3×3)
3(−6)−(−2)(−17)
=
−13
−52
=4
y=
2(−2)−(3×3)
(−17)3−(−6)2
=
−13
−39
=3
⇒
x=4&y=3
Step-by-step explanation:
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Answered by
0
Solution:
The given equations are
- 2x - 3y = 14 .....(i)
- 5x + 2y = 17 .....(ii)
To equate the coefficient of variables, we use elimination method.
Multiply (i) by 5 and (ii) by 2, we get
- 10x - 15y = 70
- 10x + 4y = 34
We see that the coefficient of x is 10 in both the equations.
On subtraction, we get
- 19y = - 36
- or, y = - 36/19
Putting y = - 36/19 in (i), we get
- 2x + 108/19 = 14
- or, 2x = 14 - 108/19
- or, 2x = 158/19
- or, x = 79/19
Answer:
Required solution is x = 79/19, y = - 36/19.
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