-2x+3y^2;3y^2+3-x^2 and x^2+x^2+y^2+5-3xy
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Answer:
We have,
(x
2
y−3y
2
+5xy
2
)−(−x
2
y+3xy
2
−3y
2
)
=x
2
y−3y
2
+5xy
2
+x
2
y−3xy
2
+3y
2
=2x
2
y+2xy
2
Step-by-step explanation:
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