Question

2x - 3y = 2, X + 2y = 8 solve by
cramers method ​

Answer 1

Step-by-step explanation:

Given, x + 2y = -1 => x + 2y + 1 = 0

2x - 3y = 12 => 2x - 3y - 12 = 0

according to Cramer's rule,

when two equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 .

then, \frac{x}{b_1c_2-b_2c_1}=\frac{-y}{a_1c_2-a_2c_1}=\frac{1}{a_1b_2-b_1a_2}then,

b

1

c

2

−b

2

c

1

x

=

a

1

c

2

−a

2

c

1

−y

=

a

1

b

2

−b

Answer 2

Answer:

answer for the given problem is given