(2x+3y) (2x+4y) factorise
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0
Answer:
4x^2+14xy+12y^2
Step-by-step explanation:
(2x+3y) (2x+4y) =4x^2+14xy+12y^2
Answered by
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(2x + 3y) (2x + 4y)
= (2x)² + (3y+4y)(2x) + (3y)(4y)
= 4x² + 14xy + 12xy
= 4x² + 26xy
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