Question

2x-3y-3=0
2x/3+4y+1/2=0
please answer me in elimination method of simultaneous linear equation?

Answer 1

$2x - 3y - 3 = 0 \\ \\ 2x - 3y = 3 - - - (1) \\ \\ \frac{2x}{3} + 4y + \frac{1}{2} = 0 \\ \\ \frac{2x}{3} + 4y = \frac{ - 1}{2} - - - (2)$

Multiplying eq'n (1) by 1 / 3 and eq'n (2) by 1 we get

$\frac{2x}{3} - \frac{3y}{3} = \frac{3}{3} \\ \\ \frac{2x}{3} + 4y = \frac{1}{2}$
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- 5y = 1 / 2

=> y = 1 / 2 / - 5

=> y = - 1 / 10

From eq'n (1)

2x - 3y = 3

=> 2x - 3( - 1 / 10 ) = 3

=> 2x + 3 / 10 = 3

=> 20x + 3 = 30

=> 20x = 30 - 3

=> 20x = 27

=> x = 27 / 20


Hope it helps