Question

2x-3y-3=0
2x/3+4y+1/2=0
please answer this simultaneous linear equations by the elimination method?

Answer 1

x = 21/20

y = -3/10

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Answer 2

Answer:

The solution of the given equations are x = $\frac{21}{20}$ and y = $\frac{-3}{10}$

Step-by-step explanation:

Given equations are

2x - 3y-3 = 0

$\frac{2x}{3}+ 4y +\frac{1}{2} = 0$

Required to solve the equations by elimination method

Solution

We have,

2x - 3y = 3 ------------------(1)

$\frac{2x}{3}+ 4y +\frac{1}{2} = 0$

Multiply on both sides with the LCM = 6 we get

4x + 24y + 3 = 0

4x + 24y = -3 -------------------(2)

To eliminate 'x', multiply (1) by '2'

4x - 6y = 6----------------(3)

(2) - (3) → 30y = -9

y = $\frac{-9}{30}$

y = $\frac{-3}{10}$

Substitute the value of y in equation (1) we get

2x - 3 × $\frac{-3}{10}$ = 3

2x = 3 - $\frac{9}{10}$ = $\frac{21}{10}$

x = $\frac{21}{20}$

∴ The solution of the given equations are x = $\frac{21}{20}$ and y = $\frac{-3}{10}$

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