Math, asked by 5111eeff, 8 months ago

(2x – 3y) (3x + y) + (x + 2y) (x – y)​

Answers

Answered by ItzMia25
2

Answer:

(6x {}^{2}  + 2xy - 9xy - 3y {}^{2}) + (x {}^{2}   - xy + 2xy - 2y {}^{2}) \\ 6x {}^{2}   - 7xy - 3y {}^{2}  + x {}^{2}  + xy - 2y {}^{2}  \\ 7x {}^{2}  - 6xy - 5y {}^{2}

Answered by asritadevi2emailcom
10

(2x - 3y)(3x + y) + (x + 2y)(x - y) \\  \\  \: in \: the \: place \: of \: (y) \: we \: can \: take \: (x) \\ (2x - 3x)(3x + x) + (x + 2y)(x - x) \\  \\ 1x + 3x + 2x + x \\  \\ 4x + 2x + x \\  \\ 6x + x \\ 6 =  {x}^{2}  \\  \\  {x}^{2}  = 6 \\  \\ 2x = 6 \\  \\ x =  \frac{6}{2}  = 3x \\  \\  =  \: 3x \: is \: the \: correct \: answer

Similar questions