Question

2x+3y+4=0; x-5y=11, Solve the set of simultaneous equations.

Answer 1

Hello here is your answer by Sujeet yaduvanshi


2x+3y=-4 *1
x-5y=11*2

2x+3y=-4
2x-10y=22
_________
13y=26
y=26/13
y=2


then,,


2x+3y=-4
2x+3(2)=-4
2x+6=-4
2x=-4-6
2x=-10
x=-10/2
x=-5



that's all

Answer 2

2x + 3y + 4 = 0

=> 2x + 3y = - 4 ------(1)

x - 5y = 11

=> 2x - 10y = 22 -----(2)

On subtracting equation 1 from 2, we get

-10y - 3y = 22 + 4

=> - 13y = 26

=> y = - 2

Now,

On substituting the value y in equation 1, we get

2x + 3(-2) = - 4

=> 2x - 6 = - 4

=> 2x = 2

=> x = 1