Question

2x-7y=7; 3x+y=22, Solve the set of simultaneous equations.

Answer 1

2x - 7y = 7 -------(1)

3x + y = 22

=> 21x + 7y = 154 -------(2)

On adding equation 1 and 2, we get

23x = 161

=> x = 7

Now,

On substituting the value of x in equation 1, we get

2(7) - 7y = 7

=> 14 - 7y = 7

=> 7 = 7 y

=> y = 1

Answer 2

Answer:

=> The value of x is 7 and y is 1.

Step-by-step explanation:

The given equation is,

$2x-7y=7$   $...(i)$

$3x+y=22$   $...(ii)$

Now, multiply the equation ( ii ) by 7,

So we get,

$=> 3x+y=22\times 7$

=> $21x+7y=154$   $...(iii)$

Now, add the equation ( i ) and ( iii ), we get

=> $2x-7y=7$

+  $21x+7y=154$

--------------------------

     $23x=161$

Divide both the sides by $23$

$=> x=7$

So, the value of x is 7.

Now, substitute the value of x as 7 in equation ( i )

=> $2x-7y=7$

=> $2( 7)-7y=7$

By further calculation we get,

=> $14-7y=7$

Subtract $14$ from both sides,

$=> -7y=-7$

Now, divide $-7$ to both sides,

$=> y = 1$

So, the value of y is 1.