2x = 3Y=4z=12 find the value of x square+y square + Z Square
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2x= 12, x= 6
3y= 12,y= 4
4z= 12 ,z=3
then 6^2+4^2+3^2=> 36+16+9= 61
3y= 12,y= 4
4z= 12 ,z=3
then 6^2+4^2+3^2=> 36+16+9= 61
ananya8974:
nyc explanation
Answered by
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X^2=12=√12=2√3/2=√3,3y=√12=2√3/3=2/√3,4z=√12=2√3/4=√3/2
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