Question

(2x+3y+4z)2, (a+b+c)2​

Answer 1

Answer: 4x + 6y + 8z, 2a + 2b + 2c

Step-by-step explanation:

2(2x + 3y + 4z) = 4x + 6y + 8z

2(a+b+c) = 2a + 2b + 2c

Answer 2

Answer:

Using identity :

$(a + b + c) ^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

$(2x + 3y + 4z) ^{2}$

$(2x )^{2} +( 3y )^{2} +( 4 {z})^{2} + 2(2x)(3y) + 2(3y )+ (4z) + 2(2x)(4z)$

$4 {x}^{2} + 9 {y}^{2} + 16 {z}^{2} + 12xy + 24yz + 16xz$