(2x- 3y+4z)² expansion
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(2x- 3y+4z)²
= (2x)² + (-3y)² + (4z)² + 2(2x)(-3y) + 2(-3y)(4z) + 2(4z)(2x)
= 4x² + 9y² + 16z² - 12xy - 24yz + 16zx Ans
Hope this helps ☺️
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