Find the value of 'k' for which the system of equations kx-y=2; 6x-2y=3 has (1) a unique solution; (2) no solution; (3) is there a value of k for which the system has a finitely many solution?
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2
Answer:
K=1
Step-by-step explanation:
Put k=1in the above equation
Answered by
1
Answer:
The given system is kx – y – 2 = 0 ……(i) 6x – 2y – 3 = 0 ……(ii) Here, a1 = k, b1 = -1, c1 =
-2, a2 = 6, b2 = -2 and c2 = -3
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