Math, asked by shhxdjaln, 7 months ago

(2x-3y-4z)^2....

solve it...don't only tell the answer...solve also..

please
will mark.your answer as brainliest​​

Answers

Answered by Anonymous
7

Step-by-step explanation:

(2x+3y+4z)2

=(2x)2+(3y)2+(4z)2+(2×2x×3y)+(2×3y×4z)+(2×4z×2x)

(∵(a+b+c)2=a2+b2+c2+2ab+2bc+2ca)

=4x2+9y2+16z2+12xy+24yz+16zx

Hence, (2x+3y+4z)2=4x2+9y2+16z2+12xy+24yz+16zx.

hope it helps you.......

Answered by shashuHP
1

Answer:

I will answer see

Step-by-step explanation:

ok bro byee

4x²-9y²-16z² or

《2x-3y-4z》²²

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