Math, asked by varanasivsv, 11 months ago

(2x+3y+4z)square
=————

Answers

Answered by marcusdemantes2002
1

With the identity of (a+b+c)^2, we can evaluate this to,

4x^2 + 9y^2 + 16z^2 + 2(6xy + 12yz + 8zx)

Hope it helps ;-)

Answered by Mercidez
4

<b><i><font face=Times New Roman size=4>Solution :

= (2x + 3y + 4z)²

= (2x)² + (3y)² + (4z)² + 2.2x.3y + 2.3y.4z + 2.4z.2x

= 4x² + 9y² + 16z² + 12xy + 24yz + 16zx Ans.

Thank You

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