(2x+3y+4z)square
=————
Answers
Answered by
1
With the identity of (a+b+c)^2, we can evaluate this to,
4x^2 + 9y^2 + 16z^2 + 2(6xy + 12yz + 8zx)
Hope it helps ;-)
Answered by
4
Solution :
= (2x + 3y + 4z)²
= (2x)² + (3y)² + (4z)² + 2.2x.3y + 2.3y.4z + 2.4z.2x
= 4x² + 9y² + 16z² + 12xy + 24yz + 16zx Ans.
Thank You
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