Question

2x+3y=5400 and 3x+2y=6100 simultaneous equations

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

x= 1500 and y= 800

Step-by-step explanation:

3x+2y=6100 ............(1)

2x+3y=5400

2x=5400-3y

x=$\frac{(5400-3y)}{2}$ ...........(2)

substituting (2) in (1)

3($\frac{5400-3y}{2}$)+2y=6100

($\frac{16200-9y}{2}$)+2y=6100

$\frac{16200-9y+4y}{2}$=6100

16200-9y+4y=6100*2

16200-5y=12200

-5y=12200-16200

y= $\frac{-4000}{-5}$ = 800

x= $\frac{5400-3y}{2}$ = $\frac{5400-3(800)}{2}$= $\frac{5400-2400}{2}$ = $\frac{3000}{2} = 1500$

∴ x= 1500 and y= 800