Question

2x-3y=7,(a+b+1)x+(a+2b+2)y=4(a+b)+1.​

Answer 1

Answer:

2x + 3y = 7 and (a + b + 1)x + (a + 2b + 2)y = 4(a + b) + 1 On comparing the given equation with standard form i.e. a1 x + b1y + c1 = 0 and a2 x + b2y + c2 = 0, we get a1 = 2, b1 = 3 and c1 = – 7 and a2 = (a + b + 1), b2 = (a + 2b + 2) and c2 = – {4(a + b) + 1}/922747/2x-3y-7-a-b-1-x-a-2b-2-y-4-a-b-1

jo upar photo h na wo 1 ke baad aayega

⇒ 2(a + 2b + 2) = 3(a + b + 1) ⇒ 2a + 4b + 4 = 3a + 3b + 3 ⇒ 2a – 3a – 3b + 4b = 3 – 4 ⇒ – a + b = – 1 ⇒ a – b = 1 …(1) On taking I and III terms, we get ⇒ 2{4(a + b) + 1)} = 7(a + b + 1) ⇒ 2(4a + 4b + 1) = 7a + 7b + 7 ⇒ 8a – 7a + 8b – 7b = – 2 + 7 ⇒ a + b = 5 …(2) Solving eqn (1) and (2), we get ⇒ 2{4(a + b) + 1)} = 7(a + b + 1) ⇒ 2(4a + 4b + 1) = 7a + 7b + 7 ⇒ 8a – 7a + 8b – 7b = – 2 + 7 ⇒ a + b = 5 …(2) Solving eqn (1) and (2), we get Now, substituting the value of a in eqn (1), we get ⇒ a – b = 1 ⇒ 3 – b = 1 ⇒ b = 2Read more on Sarthaks.com - https://www.sarthaks.com/922747/2x-3y-7-a-b-1-x-a-2b-2-y-4-a-b-1

here is your answer with full explanation

by pari