2x-3y=8 and 7x+2y=53 using elimination method
Answers
Step-by-step explanation:
2x-3y=8, 7x+2y=53
multiply by 1equation 2&2equation by 3
4x-6y=16, 21x+6y=159
25x= 175
X=7
put the value in equation 1
2x-3y=8
2(7)-3y=8
14-3y=8
3y=8-14
3y=6
y=2
(X,y)=(7,2)
Answer:
- x = 7
- y = 2
Step-by-step explanation:
Procedure:
For solving this question by elimination method, multiply the first equation by 2 and second equation by 3 so that the y coefficient of both the equations becomes 6
Given:
- 2x - 3y = 8 ----- [Equation 1]
- 7x + 2y = 53 ----- [Equation 2]
To find:
Value of x, y = ?
Solution:
Multiply the first equation by 2
2 (2x - 3y) = 2 (8)
→ 4x - 6y = 16 ----- [Equation 3]
Multiply the second equation by 3
3 (7x + 2y) = 3 (53)
→ 21x + 6y = 159 ----- [Equation 4]
Adding Equations 3 and 4,
4x - 6y = 16
{+} 21x + 6y = 159
25x = 175
⇒ x = 175 ÷ 25
⇒ x = 7
Substitute the value of x in Equation 1 to find out the value of y.
2x - 3y = 8
➝ 2 (7) - 3y = 8
➝ 8 + 3y = 14
➝ 3y = 14 - 8
➝ 3y = 6
➝ y = 6 ÷ 3
➝ y = 2