2x + 3y=sin x. Find the derivative
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2x + 3y = sinx
=> 3y = sinx - 2x
=> y = (sinx)/3 - 2x/3
differentiating wrt x ,
dy/dx = (cosx)/3 - 2/3 .......... Ans....
=> 3y = sinx - 2x
=> y = (sinx)/3 - 2x/3
differentiating wrt x ,
dy/dx = (cosx)/3 - 2/3 .......... Ans....
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