Question

There are 9 students ( 5 boys and 4 girls ) in how many ways A team of two students ( one girls & one boy ) can be selected

Answer 1

B = { B1, B2, B3, B4, B5}

Number of boys ( nB) = 5

G = { G1, G2, G3, G4}

Number of girls (nG) = 4

Total number of ways a team of one boy and one girl can be selected = Number of ordered pair formed by multiplication of set B and G

= nB × nG

= 5 × 4

= 20

Answer 2

B = { B1, B2, B3, B4, B5}

Number of boys ( nB) = 5

G = { G1, G2, G3, G4}

Number of girls (nG) = 4

Total number of ways a team of one boy and one girl can be selected = Number of ordered pair formed by multiplication of set B and G

= nB × nG

= 5 × 4

= 20