Question

2x^4-10x^3-5x^2+15x-12 divided by x^2-3

Answer 1

Answer:

p(x)=2x^4-10x³+5x²+15x-12

x= -√3/2 and √3/2

Therefore,

(x+√3/2)(x-√3/2)=0

x²-3/2=0

(2x²-3)/2=0

2x²-3=0

g(x)=2x²-3

Now divide p(x) by g(x)

The q(x) will be

=x²-5x+4

=x²-4x-x+4

=x(x-4)-1(x-4)

=(x-4)(x-1)

X=4 and x=1

Therefore, the other two zeroes are 4 and 1.

Step-by-step explanation:

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