Question

(2x + 4) (2x - 4) (4x^2 + y^2)
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Answer 1

Question :-

$( \: 2x \: + \: 4 \: ) \: ( \: 2x \: - \: 4 \: ) \: ( \: 4x^2\: + \: y^2 \: )$

Solution :-

$\implies$ $(2x)^2 \: - \: 4^2 \: {4x^2 \: + \: y^2}$

$\implies$ $(4x^2 \: - \: 16) \: {4x^2 \: + \: y^2}$

You can solve after this..

Answer 2

Answer:

4(x²-2x -y)(x² +2x+y)

Step-by-step explanation:

4x² - 8x + 8x-16 (4x² + y² )

= 16x^4 -64x²- 16y²

= 16 ( x^4 -4x² -y²)

= 4²(x²×x² -2²x²-y²)

=4(x² - 2x -y )²

= 4(x²-2x -y)(x² +2x+y)