(2x-4)(2x+4)-(x+2)(x-2)=0
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(2x-4)(2x+4)-(x+2)(x-2)=0
=>[ (2x)² - (4)² ] - [ (x)² - (2)² ] = 0
=>( 4x² - 16 ) - ( x² - 4) = 0
=> 4x² - 16 - x² + 4 = 0
=> 3 x² -12 = 0
=> 3 x² = 12
=> x² = 4
=> x = +- 2
=>[ (2x)² - (4)² ] - [ (x)² - (2)² ] = 0
=>( 4x² - 16 ) - ( x² - 4) = 0
=> 4x² - 16 - x² + 4 = 0
=> 3 x² -12 = 0
=> 3 x² = 12
=> x² = 4
=> x = +- 2
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