Question

2x+4 cube in identity expand the following inin answer.

Answer 1

using Pascal's triangle we have the coefficients for the terms as

(a+b)3→1,3,3,1

we have then

(2x+4)3=(1)(2x)3+3⋅(2x)2⋅(4)+3⋅(2x)⋅(42)+1⋅43

=8x3+48x2+96x+64

Answer 2

Step-by-step explanation:

(2x+4)^3

=8x^3+64+3.2x.2x.4+3.2x.4.4

=8x^3+64+48x^2+96x ans

on expanding.