-2x+4y+2z square
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(x+3y−4z)+(2x+y−z)+(−2x+3y−z)−(2x−4y+3z)
=(x+2x+3y+y−4z−z)+(−2x+3y−z)−(2z−4y+3z)
=(3x+4y−5z)+(−2x+3y−z)−(2x−4y+3z)
=(x+7y−6z)−(2x−4y+3z)
=x−2x+7y+4y−6z−3z
=−x+11y−9z
∴ Ans is (−x+11y−9z)
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