Math, asked by sulbharathod1, 8 hours ago

5y-4/6 + 3y+10/2 =4y+1
please answer fast​

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Answers

Answered by karthikss69
0

Answer:

How to solve your problem

5

1

4

6

+

3

+

1

0

2

=

4

+

1

5y-1 \cdot \frac{4}{6}+3y+\frac{10}{2}=4y+1

5y−1⋅64+3y+210=4y+1

Solve

1

Divide the numbers

5

1

4

6

+

3

+

1

0

2

=

4

+

1

5y-1 \cdot {\color{#c92786}{\frac{4}{6}}}+3y+\frac{10}{2}=4y+1

5y−1⋅64+3y+210=4y+1

5

1

2

3

+

3

+

1

0

2

=

4

+

1

5y-1 \cdot {\color{#c92786}{\frac{2}{3}}}+3y+\frac{10}{2}=4y+1

5y−1⋅32+3y+210=4y+1

2

Multiply the numbers

5

1

2

3

+

3

+

1

0

2

=

4

+

1

5y{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{2}{3}}}+3y+\frac{10}{2}=4y+1

5y−1⋅32+3y+210=4y+1

5

2

3

+

3

+

1

0

2

=

4

+

1

5y{\color{#c92786}{-\frac{2}{3}}}+3y+\frac{10}{2}=4y+1

5y−32+3y+210=4y+1

3

Divide the numbers

5

2

3

+

3

+

1

0

2

=

4

+

1

5y-\frac{2}{3}+3y+{\color{#c92786}{\frac{10}{2}}}=4y+1

5y−32+3y+210=4y+1

5

2

3

+

3

+

5

=

4

+

1

5y-\frac{2}{3}+3y+{\color{#c92786}{5}}=4y+1

5y−32+3y+5=4y+1

4

Add the numbers

5

2

3

+

3

+

5

=

4

+

1

5y{\color{#c92786}{-\frac{2}{3}}}+3y+{\color{#c92786}{5}}=4y+1

5y−32+3y+5=4y+1

5

+

1

3

3

+

3

=

4

+

1

5y+{\color{#c92786}{\frac{13}{3}}}+3y=4y+1

5y+313+3y=4y+1

5

Combine like terms

5

+

1

3

3

+

3

=

4

+

1

{\color{#c92786}{5y}}+\frac{13}{3}+{\color{#c92786}{3y}}=4y+1

5y+313+3y=4y+1

8

+

1

3

3

=

4

+

1

{\color{#c92786}{8y}}+\frac{13}{3}=4y+1

8y+313=4y+1

6

Subtract

1

3

3

\frac{13}{3}

313

from both sides of the equation

8

+

1

3

3

=

4

+

1

8y+\frac{13}{3}=4y+1

8y+313=4y+1

8

+

1

3

3

1

3

3

=

4

+

1

1

3

3

8y+\frac{13}{3}{\color{#c92786}{-\frac{13}{3}}}=4y+1{\color{#c92786}{-\frac{13}{3}}}

8y+313−313=4y+1−313

7

Simplify

Subtract the numbers

Subtract the numbers

8

=

4

1

0

3

8y=4y-\frac{10}{3}

8y=4y−310

8

Subtract

4

4y

4y

from both sides of the equation

8

=

4

1

0

3

8y=4y-\frac{10}{3}

8y=4y−310

8

4

=

4

1

0

3

4

8y{\color{#c92786}{-4y}}=4y-\frac{10}{3}{\color{#c92786}{-4y}}

8y−4y=4y−310−4y

9

Simplify

Combine like terms

Combine like terms

4

=

1

0

3

4y=-\frac{10}{3}

4y=−310

10

Divide both sides of the equation by the same term

4

=

1

0

3

4y=-\frac{10}{3}

4y=−310

4

4

=

1

0

3

4

\frac{4y}{{\color{#c92786}{4}}}=\frac{-\frac{10}{3}}{{\color{#c92786}{4}}}

44y=4−310

11

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

5

6

Answered by anantkshirsagar878
0

Step-by-step explanation:

this is the required value of y and as well as solution of the given questions

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