Question

2x+4z=5y+28,x+11y=5z-41,3x-3=2y+z​

Answer 1

$\frac{128443}{4140}$

Answer 2

Given :

2x+4z=5y+28,

x+11y=5z-41,

3x-3=2y+z

To Find : Solve for x , y , z

Solution:

2x+4z=5y+28,  => 2x  - 5y  + 4z  = 28    Eq1

x+11y=5z-41,     =>  x  + 11y  -  5z  = - 41    Eq2

3x-3=2y+z       =>  3x  - 2y  -   z   =  3      Eq3

Eq1  + 4 * Eq3

=> 14x - 13y  =  40

5*Eq3  - Eq2

=> 14x - 21y  =  56

=> 8y = -16  => y = -2

14x - 13y  =  40

=> 14x + 26 = 40

=> 14x = 14

=> x = 1

3x  - 2y  -   z   =  3

=> 3 + 4 - z = 3

=> z = 4

Solution is :

x = 1

y = -2

z = 4

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