Question

2x^5-3x^4+3x^2 find dy/dx. also find dy/dx at x=1

Answer 1

hope this helps you☺️☺️

Answer 2

Step-by-step explanation:

$2x^5 - 3x^4 + 3x ^{2} \\ dy \div dx = 10x ^4 - 12x ^3 + 6x \\ dy \div dx(x = 1) = 10(1) - 12 + 6 = 4$