2x + 5y = 20; 3x+6y =12 solve using cross multiplicitation
methood
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Answer:
Step-by-step explanation:
x
in the first:
x
=
18
3
−
6
y
3
x
=
6
−
2
y
Now, we replace this found
x
in the second:
2
(
6
−
2
y
)
+
5
y
=
20
12
−
4
y
+
5
y
=
20
12
+
y
=
20
y
=
8
Now, you just replace this
y
=
8
in the isolated
x
above:
x
=
6
−
2
(
8
)
x
=
6
−
16
=
−
10
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