Question

2x_5y+8=0, x_4y+7=0 method of substitution​

Answer 1

first find the value of x which is x=4y-7 then put it in 2nd eq 2(4y-7)-5y+8=0

i.e.y=2

x=4y-7=4(2)-7=1

x=1 y=2

Answer 2

Answer:

Step by step explanation

2x-5y+8=0........1.

X-4y+7=0...........2.

Now find the value of x by equation 1.

2x=-8+5y

X=-8+5y/2........3.

Now put value of x in equation 2.

X-4y+7=0

-8+5y-4y+7 = 0

2 1

-8+5y-8y+14=0

2

-3y+6=0*2

-3y=-6

Y=-6

- 3

Y=2

Now put value of y in equation 3.

X=-8+5y

2

X=-8+5*2

2

X=1

Now the value of x is 1

And value of y is 2

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