2x-5y+8=0,x-4y+7=0 solve x and y.
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Answered by
33
Hello dear...here is your answer
2x-5y+8=0
2x-5y=-8-----1
x-4y=-7--------2
multiplying by 2 in eq 2 and subtracting the equations
3y=6
y=2
put the value of y in eq 2
x-4×2=-7
x=1
hope it helps..plz mark as brainliest
2x-5y+8=0
2x-5y=-8-----1
x-4y=-7--------2
multiplying by 2 in eq 2 and subtracting the equations
3y=6
y=2
put the value of y in eq 2
x-4×2=-7
x=1
hope it helps..plz mark as brainliest
yashtyagi1:
sry but this is wrong answer.
Answered by
41
Hey there !!
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2x – 5y + 8 = 0 ...(1)
x – 4y + 7 = 0 ...(2)
From (2)
x = 4y – 7
Substituting x's value in (1)
2 ( 4y – 7 ) – 5y + 8 = 0
8y – 14 – 5y + 8 = 0
3y – 6 = 0
3y = 6
y = 6 / 3
y = 2
Putting y = 2 in (2)
x – 4 ( 2 ) + 7 = 0
x – 8 – 7 = 0
x – 1 = 0
x = 1
Thus, values of x and y are 1 and 2 respectively.
____________________________________
Hope my ans.'s helpful. (^-^)
____________________________________
2x – 5y + 8 = 0 ...(1)
x – 4y + 7 = 0 ...(2)
From (2)
x = 4y – 7
Substituting x's value in (1)
2 ( 4y – 7 ) – 5y + 8 = 0
8y – 14 – 5y + 8 = 0
3y – 6 = 0
3y = 6
y = 6 / 3
y = 2
Putting y = 2 in (2)
x – 4 ( 2 ) + 7 = 0
x – 8 – 7 = 0
x – 1 = 0
x = 1
Thus, values of x and y are 1 and 2 respectively.
____________________________________
Hope my ans.'s helpful. (^-^)
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