2x+5y=8 ,
6x-7y=10. find the value of x&y
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Answered by
0
Hi.
Here is your answer---
________________________
Given equations.
2x + 5y = 8
2x = 8 - 5y
x = (8 - 5y)/2 ------------------------------eq(i)
6x - 7y = 10 --------------------------------eq(ii)
Putting eq(i) in eq(ii)
We get,
6[(8 - 5y}/2] - 7y = 10
24 - 15y - 7y = 10
24 - 22y = 10
22y = 24 - 10
22y = 14
y = 7/11.
Putting the value of y in eq(ii),
6x - 7(7/11) = 10
6x - 49/11 = 10
6x = 10 + 49/11
6x = (110 + 49)/11
6x = 159/11
x = 53/22
Thus, the Value of the x is 53/22 and y is 7/11.
________________________
Hope it helps.
Have a nice day.
Here is your answer---
________________________
Given equations.
2x + 5y = 8
2x = 8 - 5y
x = (8 - 5y)/2 ------------------------------eq(i)
6x - 7y = 10 --------------------------------eq(ii)
Putting eq(i) in eq(ii)
We get,
6[(8 - 5y}/2] - 7y = 10
24 - 15y - 7y = 10
24 - 22y = 10
22y = 24 - 10
22y = 14
y = 7/11.
Putting the value of y in eq(ii),
6x - 7(7/11) = 10
6x - 49/11 = 10
6x = 10 + 49/11
6x = (110 + 49)/11
6x = 159/11
x = 53/22
Thus, the Value of the x is 53/22 and y is 7/11.
________________________
Hope it helps.
Have a nice day.
Answered by
0
Solution:-
given ,
2x + 5y = 8---------eq(1)
6x -7y = 10---------eq(2)
maltiply by eq(1)×3 in (-) subtract eq(2)
= 6x +15y = 24--------eq(1)
6x-7y = 10----------eq(2)
- + -
_________________________
22y = 14
y = 14/22 , y= 7/11
put value of (y) in eq (2)
6x -7×7/11 = 10
6x = 10+ 49/11
x = (110+49)/66
x= 159/66
x= 53/22
given ,
2x + 5y = 8---------eq(1)
6x -7y = 10---------eq(2)
maltiply by eq(1)×3 in (-) subtract eq(2)
= 6x +15y = 24--------eq(1)
6x-7y = 10----------eq(2)
- + -
_________________________
22y = 14
y = 14/22 , y= 7/11
put value of (y) in eq (2)
6x -7×7/11 = 10
6x = 10+ 49/11
x = (110+49)/66
x= 159/66
x= 53/22
Anonymous:
Your answer is wrong, quikly correct it
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