Math, asked by fmulanx, 5 months ago

2x - 5y = 9
3x + 4y = 2​

Answers

Answered by Anonymous
41

{\huge{\underbrace{\rm{Answer\checkmark}}}}

 \rm \:  \:  \:  \: 2x - 5y = 9.... \: (i)

 \rm \:  \:  \: 3x + 4y = 2 \:  .....(ii)

 \rm \: Multiply \: eq(i) \: by \: 3

 \rm \: and

 \rm \: eq(ii) \: by \: 2

 \rm \: Now \: new \: equations \: would \: be

 \longrightarrow \rm \: 6x - 15y = 27 \: ....(iii)

 \longrightarrow \rm \: 6x + 8y = 4 \: ....(iv)

 \rm \: Now,

 \rm \: eq(iii) - eq(iv)

  \mapsto  \rm \: 6x - 15y  - (6x + 8y)= 27 - 4

 \mapsto \:  \rm \: 6x - 15y - 6x - 8y = 23

 \mapsto \rm \:  \:  - 23y = 23

 \mapsto \boxed{ \rm{y =  - 1}}

Now,

 \rm \: put \: the \: value \: of \: y \: in \: eq(i)

 \mapsto \rm \: 2x - 5( - 1) = 9

 \mapsto \rm \: 2x + 5 = 9

 \mapsto \:  \rm \: 2x = 9 - 5

 \mapsto \:  \rm \: 2x = 4

 \mapsto \boxed{ \rm{x = 2}}

Answered by Anonymous
28

{\huge{\underbrace{\rm{Answer\checkmark}}}}

 \rm \:  \:  \:  \: 2x - 5y = 9.... \: (i)

 \rm \:  \:  \: 3x + 4y = 2 \:  .....(ii)

 \rm \: multiply \: eq(i) \: by \: 3

 \rm \: and

 \rm \: eq(ii) \: by \: 2

 \rm \: now \: new \: equations \: would \: be

 \longrightarrow \rm \: 6x - 15y = 27 \: ....(iii)

 \longrightarrow \rm \: 6x + 8y = 4 \: ....(iv)

 \rm \: now

 \rm \: eq(iii) - eq(iv)

  \mapsto  \rm \: 6x - 15y  - (6x + 8y)= 27 - 4

 \mapsto \:  \rm \: 6x - 15y - 6x - 8y = 23

 \mapsto \rm \:  \:  - 23y = 23

 \mapsto \boxed{ \rm{y =  - 1}}

{\rm{Now,}}

 \rm \: put \: the \: value \: of \: y \: in \: eq(i)

 \mapsto \rm \: 2x - 5( - 1) = 9

 \mapsto \rm \: 2x + 5 = 9

 \mapsto \:  \rm \: 2x = 9 - 5

 \mapsto \:  \rm \: 2x = 4

 \mapsto \boxed{ \rm{x = 2}}

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