Math, asked by adityaraj99732, 1 year ago

2x+6y=12,3x-6y=6 solve by substitution method​

Answers

Answered by rex1235
1

Answer:

x=18/5 y=4/5

Step-by-step explanation:

2x+6y=12

x+3y=12/2. (2common both)

x+3y=6

x=6-3y.......(3)

put the value x equal no 2

3x-6y=6

x-2y=6/3 (3 common)

x-2y=2

6-3y-2y=2

6-2=5y

y=4/5

put the value y equal 3

x=6-3x4/5

=6-12/5

=30-12/5

=18/5

Answered by omnarke22
1

Answer:

x= 18  & y=-4

Step-by-step explanation:

Equation 1: 2x+6y=12

6y=12-2x.........equ.3

Equation 2: 3x-6y=6

Now, substitute equ.3 in equ. 2

3x-12-2x=6

3x-2x=6+12

x=18

Place x=18 in equ. 1

2(18)+6y=12

36+6y=12

6y=12-36

y=-24/6

y=-4  

Therefore, x=18 and y=-4

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