Question

2x-(7-5x)/9x-(3+7x)=7/6​

Answer 1

Answer:

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$2x - \frac{(7 - 5x)}{9x} - (3 + 7x )= \frac{7}{6}$

$\frac{ {18x}^{2} - 7 + 5x - 27x - 63 {x}^{2} }{9x} = \frac{7}{6}$

$\frac{ - 45 {x}^{2} - 23x - 7}{9x} = \frac{7}{6}$

$6( - 45 {x}^{2} - 23x - 7) = 63x$

$- 270 {x}^{2} - 138x - 42 = 63x$

$- 270 {x}^{2} - 201x - 42 = 0$

$- (270 {x}^{2} + 201x + 42) = 0$

$270 {x}^{2} + 201x + 42 = 0$

$3(90 {x}^{2} + 67x + 14) = 0$

$90 {x}^{2} + 67x + 14 = 0$

see in the image above for next step:-