calculate the mole fraction of 30% by mass of ethanol solution
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Molecular mass of C2H6O (ethanol) = 46amu
molecular mass of H2O = 18amu
no. of moles = given mass/molecular mass
therefore, no. of moles of ethyl alcohol (ethanol) = 46/(molecular mass of C2H6O)
= 46/4
= 1 moles
no.of moles of H2O=90/(molecular mass of H20)
=90/18
= 5 moles
total moles = moles of ethanol + moles of H2O
= 1+5=6 moles
mole fraction of sub.= moles of sub./total moles
mole fraction of ethanol= 1/6
=0.1666
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0.166 is the correct answer
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